## How do you solve molality problems?

Table of Contents

Molality is the number of moles of solute per kilogram of solvent.

- Step 1 – Determine number of moles of sucrose in 4 g. Solute is 4 g of C12H22O11
- Step 2 – Determine mass of solvent in kg. density = mass/volume.
- Step 3 – Determine molality of the sugar solution. molality = molsolute / msolvent

## How do you find molality in chemistry?

Molality = nsolute / m solvent = msolute / (W solute * m solvent)

- nsolute is amount of the solute (in moles)
- msolvent is a mass of the solvent (in kg)
- msolute is a mass of the solute (in g)
- W solute is a molar mass of the solute (in g/mol).

**What is the molarity of 15.0 g KCl dissolved in 1000 g of water the density of the solution is 0.997 g ml?**

Given: the mass of solute (KCl) = 10 g, the mass of solvent (water) = 1000 g = 1 kg, density of solution = 0.997 g cm-3, To Find: molarity =? molality =? Ans: The molarity of the solution is 0.1325 mol L-1 or 0.1325 M, the molality of the solution is 0.1342 mol kg-1 or 0.1342 m.

**What is the molality m of 0.75 moles substance that is dissolved in 2.5 liter of solvent?**

Example #3: What is the molality when 0.750 mol is dissolved in 2.50 L of solvent? The answer is 0.300 m.

### How do you calculate molality from grams and mL?

- Conversion from Molarity to Molality.
- Problem: Find the molality of 18 M H2SO4.
- Make an assumption.
- Assume you have 1 L of solution.
- Find the total mass of the solution.
- Multiply 1 L X the density (1.84 g/mL) X 1000 mL/L.
- Calculate the grams of the solute.
- 18M means 18 moles of sulfuric acid per one liter of solution.

### How do you calculate the molality of NaCl?

If a solution of salt water contains 29 grams of sodium chloride (NaCl) and that salt is dissolved in 1000 grams of water, the molarity can be determined by converting the grams of sodium chloride to moles and dividing that by the mass of the water converted to kilograms.

**What is the molarity of a solution that was prepared by dissolving 14.2 g of NaNO3?**

1. What is the molarity of a solution that was prepared by dissolving 14.2 g of NaNO3 in enough water to make 350 mL of solution? 14.26 Nallch imel NaNo – 0.167 moi.

**What is the molality of a solution containing 15.0 g NaCl dissolved in 50.0 g?**

1 Answer. The molality of the solution is 1.388 m.

#### What is the number of moles of solute in 250 mL of a 0.4 m solution?

There are 0.1 moles of solute in 250 mL of 0.4 M solution.

#### What is the molarity of 0.30 liter solution containing 0.50 moles of NaCl?

concentration=[NaCl(aq)]=0.50⋅mol0.30⋅L=1.67⋅mol⋅L−1 .