How do you write an equation of a line that is perpendicular to another line?

Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6. Rearranged, it is –x/2 + y = 6.

How do you make a box in LaTeX?

The \makebox command creates a box to contain the text specified. The width of the box is specified by the optional width argument. The position of the text within the box is determined by the optional position argument. The \mbox command creates a box just wide enough to hold the text created by its argument.

Which is an equation for a line that is perpendicular to the graph of the line y 2x 3?

General equation of a line perpendicular to y = − 2x + 3 is y = 1/2x + k where is the k is the y intercept.

How do you tell if a line is perpendicular with an equation?

Perpendicular lines intersect at right angles to one another. To figure out if two equations are perpendicular, take a look at their slopes. The slopes of perpendicular lines are opposite reciprocals of each other. Their product is -1!

How do you find a perpendicular slope?

The perpendicular slope will be the opposite reciprocal of the original slope. Use the slope-intercept form (y = mx + b) and substitute in the given point and the new slope to find the intercept, b. Convert back to standard form of an equation: ax + by = c.

What is the equation of the line that is perpendicular to the given line and passes through the point 3 0 )?

Using this slope and the given point, we can find the equation for the line. The line perpendicular to f(x) that passes through (3, 0) is g(x)=−13x+1 g ( x ) = − 1 3 x + 1 .

How do you make a rectangular box in LaTeX?

If you use the options colframe=black,colback=white,arc=0pt,outer arc=0pt you will get a rectangular box with white interior.